Integrand size = 22, antiderivative size = 84 \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=-\frac {A \sqrt {a+b x^2}}{5 a x^5}+\frac {(4 A b-5 a B) \sqrt {a+b x^2}}{15 a^2 x^3}-\frac {2 b (4 A b-5 a B) \sqrt {a+b x^2}}{15 a^3 x} \]
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Time = 0.03 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {464, 277, 270} \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=-\frac {2 b \sqrt {a+b x^2} (4 A b-5 a B)}{15 a^3 x}+\frac {\sqrt {a+b x^2} (4 A b-5 a B)}{15 a^2 x^3}-\frac {A \sqrt {a+b x^2}}{5 a x^5} \]
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Rule 270
Rule 277
Rule 464
Rubi steps \begin{align*} \text {integral}& = -\frac {A \sqrt {a+b x^2}}{5 a x^5}-\frac {(4 A b-5 a B) \int \frac {1}{x^4 \sqrt {a+b x^2}} \, dx}{5 a} \\ & = -\frac {A \sqrt {a+b x^2}}{5 a x^5}+\frac {(4 A b-5 a B) \sqrt {a+b x^2}}{15 a^2 x^3}+\frac {(2 b (4 A b-5 a B)) \int \frac {1}{x^2 \sqrt {a+b x^2}} \, dx}{15 a^2} \\ & = -\frac {A \sqrt {a+b x^2}}{5 a x^5}+\frac {(4 A b-5 a B) \sqrt {a+b x^2}}{15 a^2 x^3}-\frac {2 b (4 A b-5 a B) \sqrt {a+b x^2}}{15 a^3 x} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.74 \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=\frac {\sqrt {a+b x^2} \left (-3 a^2 A+4 a A b x^2-5 a^2 B x^2-8 A b^2 x^4+10 a b B x^4\right )}{15 a^3 x^5} \]
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Time = 2.84 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.65
method | result | size |
pseudoelliptic | \(-\frac {\left (\left (\frac {5 x^{2} B}{3}+A \right ) a^{2}-\frac {4 x^{2} b \left (\frac {5 x^{2} B}{2}+A \right ) a}{3}+\frac {8 A \,b^{2} x^{4}}{3}\right ) \sqrt {b \,x^{2}+a}}{5 a^{3} x^{5}}\) | \(55\) |
gosper | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (8 A \,b^{2} x^{4}-10 B a b \,x^{4}-4 a A b \,x^{2}+5 a^{2} B \,x^{2}+3 a^{2} A \right )}{15 a^{3} x^{5}}\) | \(59\) |
trager | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (8 A \,b^{2} x^{4}-10 B a b \,x^{4}-4 a A b \,x^{2}+5 a^{2} B \,x^{2}+3 a^{2} A \right )}{15 a^{3} x^{5}}\) | \(59\) |
risch | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (8 A \,b^{2} x^{4}-10 B a b \,x^{4}-4 a A b \,x^{2}+5 a^{2} B \,x^{2}+3 a^{2} A \right )}{15 a^{3} x^{5}}\) | \(59\) |
default | \(B \left (-\frac {\sqrt {b \,x^{2}+a}}{3 a \,x^{3}}+\frac {2 b \sqrt {b \,x^{2}+a}}{3 a^{2} x}\right )+A \left (-\frac {\sqrt {b \,x^{2}+a}}{5 a \,x^{5}}-\frac {4 b \left (-\frac {\sqrt {b \,x^{2}+a}}{3 a \,x^{3}}+\frac {2 b \sqrt {b \,x^{2}+a}}{3 a^{2} x}\right )}{5 a}\right )\) | \(102\) |
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Time = 0.26 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.69 \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=\frac {{\left (2 \, {\left (5 \, B a b - 4 \, A b^{2}\right )} x^{4} - 3 \, A a^{2} - {\left (5 \, B a^{2} - 4 \, A a b\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{15 \, a^{3} x^{5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 355 vs. \(2 (76) = 152\).
Time = 1.21 (sec) , antiderivative size = 355, normalized size of antiderivative = 4.23 \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=- \frac {3 A a^{4} b^{\frac {9}{2}} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} - \frac {2 A a^{3} b^{\frac {11}{2}} x^{2} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} - \frac {3 A a^{2} b^{\frac {13}{2}} x^{4} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} - \frac {12 A a b^{\frac {15}{2}} x^{6} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} - \frac {8 A b^{\frac {17}{2}} x^{8} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} - \frac {B \sqrt {b} \sqrt {\frac {a}{b x^{2}} + 1}}{3 a x^{2}} + \frac {2 B b^{\frac {3}{2}} \sqrt {\frac {a}{b x^{2}} + 1}}{3 a^{2}} \]
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Time = 0.27 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.14 \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=\frac {2 \, \sqrt {b x^{2} + a} B b}{3 \, a^{2} x} - \frac {8 \, \sqrt {b x^{2} + a} A b^{2}}{15 \, a^{3} x} - \frac {\sqrt {b x^{2} + a} B}{3 \, a x^{3}} + \frac {4 \, \sqrt {b x^{2} + a} A b}{15 \, a^{2} x^{3}} - \frac {\sqrt {b x^{2} + a} A}{5 \, a x^{5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 176 vs. \(2 (72) = 144\).
Time = 0.34 (sec) , antiderivative size = 176, normalized size of antiderivative = 2.10 \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=\frac {4 \, {\left (15 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{6} B b^{\frac {3}{2}} - 35 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{4} B a b^{\frac {3}{2}} + 40 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{4} A b^{\frac {5}{2}} + 25 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} B a^{2} b^{\frac {3}{2}} - 20 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} A a b^{\frac {5}{2}} - 5 \, B a^{3} b^{\frac {3}{2}} + 4 \, A a^{2} b^{\frac {5}{2}}\right )}}{15 \, {\left ({\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} - a\right )}^{5}} \]
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Time = 5.14 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.69 \[ \int \frac {A+B x^2}{x^6 \sqrt {a+b x^2}} \, dx=-\frac {\sqrt {b\,x^2+a}\,\left (5\,B\,a^2\,x^2+3\,A\,a^2-10\,B\,a\,b\,x^4-4\,A\,a\,b\,x^2+8\,A\,b^2\,x^4\right )}{15\,a^3\,x^5} \]
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